#nongasal
#pakaicara
#bukanpilihanganda
5a dan 130, saling bertolak belakang, maka
5a = 130
a = 130/5
a = 26
3b - 4 dan 71 saling bertolak belakang maka
3b - 4 = 71
3b = 71 + 4
3b = 75
b = 75/3
b = 25
2c + 11 dan 71 saling berpelurus, maka
2c + 11 + 71 = 180
2c + 82 = 180
2c = 180 - 82
2c = 98
c = 98/2
c = 49
5x + 4 dan 49 saling bertolak belakang
5x + 4 = 49
5x = 49 - 4
5x = 45
x = 45/5
x = 9
8y - 5 dan 49 saling berpelurus, maka
8y - 5 + 49 = 180
8y + 44 = 180
8y = 180 - 44
8y = 136
y = 136/8
y = 17
# Jawaban oleh belajar bareng okta
Jawab:
jenis sudut
i) 5a = 130 ( bertolakbelakang)
a = 26
ii) 3b - 4 = 71 (bertolak belakang)
3b = 75
b = 25
iii) 2c + 11 + 71 = 180 ( berpelurus)
2c + 82 = 180
2c = 180 -82
2c = 154
c = 77
iv. 5x + 4 = 49 (bertolakbelakang)
5x = 49 - 4
5x = 45
x = 9
v. 8y - 5 + 49 = 180 (berpelurus)
8y + 44 = 180
8y = 180- 44
8y = 136
y = 17
